Group Rings
For any finite group
the group ring
of
is the group of formal linear combinations of elements of
, with coefficients in
and multiplication defined on the basis elements and then extended linearly:

Even though it is called a group ring this important object actually has the structure of a
-algebra. That is it is both a ring, and a finite dimensional vector space over
. In reading what follows it is important to keep clear in your mind when we are treating
as a ring, and when we are treating it as a vector space over
.
A representation of of a a
-algebra
on a finite dimensional vector space
is an algebra homomorphism:

Here
is the space of endomorphisms of
. If
is of dimension
then once a basis has been chosen
may be thought of as the algebra of
by
matrices.
Every representation
of a group
on a vector space
lifts naturally to a representation
of the algebra
on the same vector space.

Since these two things are really “the same” in a certain category theoretical sense which I don’t really want to go into just now (I’m starting to sound like a physicist, aren’t I?), we usually drop the hat and swap back and forth freely between the representation of the group, and the representation of the associated group ring.
Now, there are two natural representations of
on the group ring thought of as a vector space. Firstly, right multiplication:

given by:

and secondly left multiplication by the inverse:

given by:

The linear map:

is an intertwiner between these two representations. In other words, upto conjugation they are really the same representation

On the dual space
of linear functions on
we have:

given by:
![<br />
\begin{align*}<br />
R^*(x).f [g] & = f[gx^{-1}] \\<br />
L^*(x).f [g] & = f[x g]<br />
\end{align*}<br />](http://analogical-engine.com/wordpress/wp-content/cache/tex_c8a4b65a5689dde14df395ea5cd07558.png)
One can check that:
![<br />
\begin{align*}<br />
R^*(x).f[R(x).g] & = f[g] \\<br />
L^*(x).f[L(x).g] & = f[g]<br />
\end{align*}<br />](http://analogical-engine.com/wordpress/wp-content/cache/tex_6263c1095af290d95999f6605b3c3d7e.png)
Since the left and right actions clearly commute, we actually have a representation:

given by:

Similarly we have:

given by:
![(L^* \otimes R^*)(x,y) f[z] = f[ x z y^{-1}]](http://analogical-engine.com/wordpress/wp-content/cache/tex_516b79e9ed84ed80abe62e1aaf868086.png)
The linear map:

is an intertwiner between these two representations of
.
![<br />
\begin{align*}<br />
\psi((L\otimes R)(x,y).g)[z] & = \psi(x^{-1}g y)[z] \\<br />
& = \delta_{x^{-1}g y} [z] \\<br />
& = \delta_g [x z y^{-1} ] \\<br />
& = (L^* \otimes R^*)(x,y).(\psi(g)[z])<br />
\end{align*}<br />](http://analogical-engine.com/wordpress/wp-content/cache/tex_29debb76287e207909365cde4caec917.png)
The inverse map is given by:

We have all the ingredients now to prove the Artin-Wedderburn theorem for semisimple rings.